Hai, I am posting the work. This work is related to mechanical engineering and maintenance engineering subjects. In that work we have to use and GRANTAEDUPACK 2020 software and it was a problematic

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ADVANCED MATERIALS AND MATERIAL SELECTION

By Name

Course

Instructor

Institution

Location

Date

ADVANCED MATERIALS AND MATERIAL SELECTION

Hai,   I am posting the work. This work is related to mechanical engineering and maintenance engineering subjects.  In that work we have to use and GRANTAEDUPACK 2020 software and it was a problematic 1

QUESTION 1

Part 1

Hai,   I am posting the work. This work is related to mechanical engineering and maintenance engineering subjects.  In that work we have to use and GRANTAEDUPACK 2020 software and it was a problematic 2

Function

Pressure vessel

Objective

Minimize the cost, C

Constraints

Length, L specified

Diameter (2R) ,Specified

Must not fail by fast fracture

Material must not fail by buckling

Must not fail by yielding

Free Variables

Choice of Material

Thickness ,t

Hai,   I am posting the work. This work is related to mechanical engineering and maintenance engineering subjects.  In that work we have to use and GRANTAEDUPACK 2020 software and it was a problematic 3


The cost for the pressure vessel C is given by the product of mass and cost per kilogram Cm of material

Failure of material due to yielding

Allowable stress needs to be less than yield material strength, to prevent material yielding

The cylindrical pressure vessel designed need to withstand both circumferential and longitudinal stress. The design material to withstand circumferential stress must be higher than longitudinal stress (Ashby, 2013)

Stress in walls of pressure vessel caused by pressure p needs not be exceed

Substituting the equation to eliminate t which is a free variable (Abdullah, 2012)

Material cost

Material cost

The material performance index for Yielding;

The mass of material is minimized through selecting materials with largest index values

The cost of material is minimized through selecting materials with largest index values

Material failure due to fast fracture

Substituting the value t which is a free variable in the equation;

And the cost is given by