Quiz 9 Worksheet

1. Draw a Punnett Square (table) for the following cross:

Aa x aa

Draw the Punnett Square on your own and submit it here.

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2.What is the probability of a zygote with genotype Aa?Group of answer choices

a)0.75

b)0.25

c)other

d)0

e)0.50

f)1.0

3.What is the probability of a zygote with genotype aa?Group of answer choices

0.25

1.0

0.5

0.75

4. What is the probability of a zygote with genotype AA? Group of answer choices

0.5

1.0

0.75

0.25

5.The allele for round seeds (R) is dominant to the allele for wrinkled seeds (r).  You cross two plants that are heterozygous at the R locus.  

Draw the Punnett Square:

6.What is the probability of getting an offspring plant with wrinkled seeds? Group of answer choices

0.25

0.5

1.0

0.75

7.The allele for round seeds (R) is dominant to the allele for wrinkled seeds (r). You buy a pea plant that has round seeds.  You want to know whether it is homozygous or heterozygous.  

How would you test this (be very specific – what cross would you perform)? 

8. In humans, brown eyes (B) are dominant over blue (b). A brown-eyed man marries a blue-eyed woman and they have three children.  Two are brown-eyed and one is blue-eyed. Draw the Punnett square that illustrates this and submit it here.

 (there are a handful of genes involved in eye color, but blue eyes are specified by a mutation in a single gene, HERC2.)

9. Polydactyly (extra fingers or toes) is (usually) an autosomal dominant trait. If a person who is heterozygous for the allele that causes polydactyly has a child with a person that has the normal number of fingers and toes, what is the probability that they will have a child with polydactyly? 

Group of answer choices

0.75

1.0

0.25

0.5


10. A man with group AB blood marries a woman with group O blood. What blood types are possible in this couple’s offspring? (select all possible blood types)

Group of answer choices

Type B

Type O

Type A

Type AB

 

Question 111 pts

Ichthyosis is an X-linked recessive disorder that causes scaly skin. If a female carrier of the disease has children with a normal male, what is the probability of each son having the disease? 

Group of answer choices

1.0

0.75

0.25

0

0.5

 

Question 121 pts

What is the probability of each daughter having the disease?

Group of answer choices

0.75

1.0

0.5

0.25

0

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