The Excel function =RANDBETWEEN(a,b) generates a random integer value between a and b. Open Excel. Copy and paste the Excel function into 30 cells (rows) starting at Column A at A1. Create 30 random v
Excel provides functions for computing the mean, median, and mode. We illustrate the use of these functions by computing the mean, median, and mode for the starting salary data in Table 3.1. Refer to Figure 3.2 as we describe the tasks involved. The formula worksheet is in the background; the value worksheet is in the foreground.
Figure 3.2Excel Worksheet Used to Compute the Mean, Median, and Mode for the Starting Salary Data
Enter/Access Data: Open the file StartingSalaries. The data are in cells B2:B13 and labels are in column A and cell B1.
Enter Functions and Formulas: Excel’s AVERAGE function can be used to compute the mean by entering the following formula in cell E2:
Supplementary Exercises
Americans Dining Out. Americans tend to dine out multiple times per week. The number of times a sample of 20 families dined out last week provides the following data.
Compute the mean and median.
Answer
The data in ascending order follow.
Position | Value | Position | Value |
11 | |||
12 | |||
13 | |||
14 | |||
15 | |||
16 | |||
17 | |||
18 | |||
19 | |||
10 | 20 |
The mean is 2.95 and the median is 3.
Compute the first and third quartiles.
Answer
First quartile or 25th percentile = 1 + . 25(1 − 1) = 1
Third quartile or 75th percentile = 4 + . 75(5 − 4) = 4.75
Compute the range and interquartile range.
Answer
The range is 7 and the interquartile range is 4.75 − 1 = 3.75.
Compute the variance and standard deviation.
Answer
The variance is 4.37 and standard deviation is 2.09.
The skewness measure for these data is .34. Comment on the shape of this distribution. Is it the shape you would expect? Why or why not?
Answer
Because most people dine out a relatively few times per week and a few families dine out very frequently, we would expect the data to be positively skewed. The skewness measure of 0.34 indicates the data are somewhat skewed to the right.
Do the data contain outliers?
Answer
The lower limit is −4.625 and the upper limit is 10.375. No values in the data are less than the lower limit or greater than the upper limit, so there are no outliers.