I have to complete questions 12-15

3. Mwater = 2,543 g wet soil – 2,085 g dry soil = 458 g H2O

4. Ɵg = = 0.22 g/g

5. Ɵv = * = 0.29 cm3/cm3

6. ΡB = = 1.32 g/cm3

7. PS = 1 – = 0.50 cm3/cm3

8. AFPS = PS - Ɵv = 0.50 cm3/cm3 - 0.29 cm3/cm3 = 0.21 cm3/cm3

9. WFPS = PS - AFPS = 0.50 cm3/cm3 - 0.21 cm3/cm3 = 0.29 cm3/cm3

10. (Ɵv day playground is installed) = (Ɵv of sample from 3 days ago) – (Ɵv decrease/day)*(# of days)

Ɵv = 0.29 cm3/cm3 – (0.03 cm3/cm3 * 4 days)

Ɵv = 0.29 cm3/cm3 – 0.12 cm3/cm3 = 0.17 cm3/cm3

1. If: Ɵv = , substitute x for masswater and 0.17 cm3/cm3 for Ɵv; volume is known

0.17 cm3/cm3 =

x = 0.17 cm3/cm3 * 1570.8 cm3 = 267 g H2O

Ɵg = = = 0.12 g/g