need only part two parts(e,f)
Answer to question #a:
Average cycle time for element 1 = ( 0.44 + 0.5 + 0.43 + 0.45 + 0.48 +0.46) / 6 = 0.46
Average cycle time for element 2 = ( 1.5 + 1.54 + 1.47 + 1.51 + 1.49 + 1.52)/ 6 = 1.505
Average cycle time for element 3 = ( 0.84 + 0.89 + 0.77 + 0.83 + 0.85 + 0.80) /6 = 0.83
Average cycle time for element 4 = ( 1.1 + 1.14 + 1.08 + 1.2 + 1.16 + 1.26)/6 = 1.156
Answer to question # b:
Normal time for each element = Average cycle time for the element x Performance rating %/100
Thus Normal time for each element as follows :
| Element | Average cycle time | Performance rating % | Normal time |
| 0.46 | 85 | 0.46 x0.85 = 0.391 | |
| 1.505 | 100 | 1.505 x 1 = 1.505 | |
| 0.83 | 110 | 0.83 x 110/100 = 0.913 | |
| 1.156 | 95 | 1.156 x 95/100 = 1.0982 |
Answer to question #c :
Standard time for each element = Normal time ( 1 + Allowance factor in % /100)
Here, Allowance factor = 15%
Therefore Standard time = 1.15 x Normal time
Thus Standard time for each element and standard time for the task ( i.e. sum of all 4 elements ) is as follows :
| Element | Normal time | Standard time |
| 0.391 | 0.391 x 1.15 = 0.449 | |
| 1.505 | 1.505 x 1.15 = 1.730 | |
| 0.913 | 0.913 x 1.15 = 1.05 | |
| 1.0982 | 1.0982 x 1.15 = 1.263 | |
| Standard time for the task: | (0.449 + 1.730 + 1.05 + 1.263) = 4.492 |
STANDARD TIME FOR THE TASK = 4.492
Answer to question #d
Takt time will be defined as “Net available time for production / Number of units to be produced”
Since it is a 8 hour shift, net available time = 60 x 8 = 480 minutes
Number of parts to be produced = 110
Therefore, Takt time = 480/110 = 4.363
TAKT TIME = 4.363 MINUTES
