Week 1: Student Response to Discussion

Jun 5, 2017Jun 5 at 9:21pm

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Using my birth date 11/9/88 to solve the following equations using the following variables A, B, and C. A=11 B=9=88.

My problems ended up looking like this: 1. (11^3) – (-9^3) 2. (11- -9) +(11^2 + 11(-9) + -9^2 and the final problem, 3. (-9 – 88) / (2(-9) – 11). When solving my first problem I knew that with the exponent number 3 it would look like this (11x11x11) = 1,331 and (-9x -9x -9) = -729. So, then it is laid out like this (1,331) – (-729) but, we are subtracting a negative integer it changes to positive so, now it looks like this 1,331 + 729 = 2060. The second problem as shown above is would be written like this (11- -9) + (11^2 +11(-9) +(-9^2). Then it would look like this (11+9) (121 – 99 + 81) then (20) (103) =2060. For my last problem (-9 – 88) / 2 (-9) – 11) next my answer came to this (-97) / (-29). Now I am going to take the dividend by the divisor number and reduce my answer to lowest terms. My answer to (-97) / (-29) = 3.34. Since a negative and a negative is divided together my answer becomes positive. This was a very big deal for me considering I struggle very badly when it comes to math so any positive criticism would be greatly appreciated. Thanks in advance.