Week 5: Student Response To Discussion 1
Collapse SubdiscussionKelley Everett
Kelley EverettThursdayJul 6 at 12:51am
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MATH 221
Week 5: Discussion 1
Kelley Everett
For this week’s discussion, I am to complete equation # 26 on page 345,# 106 on page 346, and #38 on page 353 from our math E-book, Elementary and Intermediate Algebra.
I will begin by writing the formula for factoring trinomials from exercise # 26:
x2 +bx+c :
Equation:
x2 +3x+3 first 3 is the greatest common factor(GCF) and we must find 2 integers that equals 3 and is the sum of 3x(‘bx’ in formula)
2
1x3 neither of these coefficients is the sum of 3 when adding the numbers and thus cannot be factored into the equation. Therefore the equation is a prime polynomial.
Exercise # 106
This equation was difficult and I may require assistance upon completion. I am to factor the 4 term polynomial by grouping.
The equation:
ac+xc+aw2 +xw2 we have 4 terms and we first factor like terms
xw2 +aw2+ac+xc need to reverse the terms
x(w+a)2 +c(a+x) paired 1st and 2nd like terms
(xw+a)2 this is a perfect square result
Exercise #38
This method requires the AC method to solve the trinomial equation:
The equation:
15x2 -7x-2 First we must look at our coefficients: a=15
b= -7 and c= -2-multiple ac cofficients to obtain the product for ‘ac’ and sum of ‘-2)
15 x (-2) = -30 now we must find 2 integers from -30 that will equal -7
-10 x3=-30 -10+3=-7-so now we rewrite our polynomial
15x2 + -10x+ 3x -2 now we group our like terms in this 4 term polynomial
(3x + -2)5x +(3x-2)1 divide 5 into 15 and 10, then place results in parenthesis
Factor out the common common factors: 3x and1
(3x + -2)(5x+1) answer
Use Foil method to check answer=FIRST-OUTER-INNER-LAST
3x x 5x=15x2
3x x -1= 3x
2 x 5x=-10x
-2 x-1=-2
152 +-3x+ -10x + -2= 15x2 -7x-2
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As mentioned above, I will require some guidance with problems solving if equations are incorrect. As normal, I work my problems out first without looking at other’s work. Thank you.