Week 2: Student Response to Discussion Two

YesterdayJul 26 at 3:44am

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Hello,

Attached is my handiwork.

My first Compound Inequality was an And:

-2 < -1-4x < 12

First I added 1 to all three portions.

-1 < -4x < 13

Then I divided all three by -4, which reverses the signage.

1/4 > x > -13/4 (-13/4 reduces to -3 1/4)

Which means x = (-3 1/4 , 1/4), in that order because we read the line graph from left to right.

This And expression means that the variable has a possibility to be between -3 1/4 and 1/4, which is proven by the intersection on the line graph.

My second inequality was an Or expression. I know this to be true because the word Or is included in the expression, which tells me that the solution can be A , B or both.

2x-7 ≤ 5 or 5-2x > 3

I treated each set individually. I added 7 on the left and subtracted 5 on the right side.

2x ≤ 5 or -2x > -2

Next, I divided each side by 2 and -2 respectively, reversing my sign because of the -2.

x ≤ 6 or x<1

Then after a quick linear graphical artification, I concluded x = (-∞,6].

Hard bracket because of the ≤.

Neither of my problems included a union because both graphs had an intersection and no unused solutions in between.

Thanks!

-Fish