Week 1: Student Response to Discussion One

Nicole Morain

Jul 20, 2017Jul 20 at 12:49pm

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I am solving for #24. I found this assignment a bit confusing as far as trying to explain everything. I am not very good at explaining math hence the reason why I was never that great with word problems. Once you mix numbers with letters, everything gets confusing.

The rational expressions that I was provided to work with are:

y2 – 25 –6y

37 2p – 4p2

A Domain is considered to be any number that is a part of the fraction that does not cause the denominator to equal zero. The fraction cannot be divided by zero therefore, the denominator cannot equal zero. When using real numbers, dividing a number by zero will simply equal zero therefore when dividing rational expressions, the denominator will be undefine if divided by zero.

My first expression consists of a variable that causes the excluded value to be zero.

By subtracting -6 from all sides, the answer that I am left with is zero.

-6y = 0

-6 -6 Y = 0

The y in this expression is equal to zero causing the expression to be undefined.

The Domain of this expression written in set notation is D = { y|y Î Â, y = 0}. The  represents a real number. The = means that the variable is equal to zero.

For my second expression, the numerator is a real number so I factor 2p out of the denominator. The expression now reads 37

2p(1-2p)

The expression can now be set to zero because 2p(1-2p) when solved becomes the original denominator of 2p-4p2.

Both of my expressions contain excluded values and the reason that they must be excluded is because the values cause the expression to be zero.