Q5 Two containers ( call them A and B ) with the same initial volume , V=47L, hold the same amount of monatomic ideal gas ,say helium , at the same initial temperature TI =304 K and the same initial
at constant volume
specific heat capacity at constant volume is Cv= (3/2)*R = (3/2)*8.314 = 12.47
heat energy given is Q = n*Cv*dT
usind ideal gas equation
P*V = n*R*T
1.013*10^5*47*10^-3= n*8.314*304
n = 1.88 moles
Q = n*Cv*dT = 1.88*12.47*dT
at constant pressure
Cp = (5/2)*R = (5/2)*8.314 = 20.785
Q = n*Cp*dT
Q = 1.88*20.785*dT
then
at constant volume
Q = 1.88*12.47*dT
3183 = 1.88*12.47*dT
dT = 135.77 K
atconstant pressure
Q = 1.88*20.785*dT
3183 = 1.88*20.785*dT
dT = 81.45 K