Q5 Two containers ( call them A and B ) with the same initial volume , V=47L, hold the same amount of monatomic ideal gas ,say helium , at the same initial temperature TI =304 K and the same initial

at constant volume

specific heat capacity at constant volume is Cv= (3/2)*R = (3/2)*8.314 = 12.47

heat energy given is Q = n*Cv*dT

usind ideal gas equation

P*V = n*R*T

1.013*10^5*47*10^-3= n*8.314*304

n = 1.88 moles

Q = n*Cv*dT = 1.88*12.47*dT

at constant pressure

Cp = (5/2)*R = (5/2)*8.314 = 20.785

Q = n*Cp*dT

Q = 1.88*20.785*dT

then

at constant volume

Q = 1.88*12.47*dT

3183 = 1.88*12.47*dT

dT = 135.77 K

atconstant pressure

Q = 1.88*20.785*dT

3183 = 1.88*20.785*dT

dT = 81.45 K