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# ""-Verify that the frequency of AC voltage is correct and in agreement with how fast you were turning the generator. Verify that the voltages are 120...

""-Verify that the frequency of AC voltage is correct and in agreement with how fast you were turning the generator. Verify that the voltages are 120 degrees celcius out of phase. Calculate the pwoer dissapated across the 3 resistors. How does the voltage you measured on the DMM compare to the voltage calculated from the graph?(my data: 13 rotations, 8 seconds, 1.625 rev/s.)-Compare the voltage you need to measure for 100 Watts output power. Make your logic easy to follow. Attach PC output chart and show measurements for the 100 Watt output.-Calculate the force on the crank needed to generate the 100 W. Is the force on the crank to generate 100 W greater or less than the force to lift a 5kg weight?-Does the induced voltage increase as you turn the handle faster? Why? Explain using Faradays Law.Additional Data:-DMM V=2.90V-The current or voltage from eah coil is out of phase by 120 degrees Celcius becasue of the position of the coils in the stator.-The electrical power coming from the wall plugs is AC power with Vmax in the range 155 to 180 Volts and a frequency of 60 Hz or 60 cycles per second.-The average value of sin^2 (2ft) over one cycle is 1/2 so I^2=I^2max/2 and I=Imax/sqrroot of 2= 0.707Imax. Similarly V=vmax/sqrroot of 2=0.707Vmax.-The light bulbs did not light up when we turned the handle of the generator with the power supply turned off.-The light bulbs did turn on when we turned on the power supply and adjusted to a voltage of 5 volt but did not turn the generator on.-The lights did turn on with the power supply turned on and set at 5 volts and we turned the handle generator.-The light bulbs became brighter as we turned the handle faster-The light bulbs became dimmer when we lowered the voltage in the power supply while turning the generator at the same rate.-Each set of two resistors has a total resistance of R=0.25Ohm (Each single resistor has R=0.5Ohm)-Verify that V=0.707 Vmax where V is the voltage measured on the DMM and Vmax is measured on teh PC printout. (I GOT: V=2.5 VMAX=4.3)-Compute the total power dissipated in the three resistors from the printout of the voltages from your PC when you are turning at the rate of about 1 cycle per second. Assume that each resistor set has a total resistance of 0.25 ohm. Keep in mind that the total power you are generating is three times measured across a single set.(I GOT: V/R=2.9^2/.25=33.64v/100.92v=1 resistor/3 resistors)-Mechanical power is defined by P=F*V=force times velocity, where F is a force measured in Newtons and v is the velocity in the same direction measured in m/s. The velocity is the rotation velocity of the crank while you are turning the generator. The length of the crank is 0.28m. Compute the force needed to generate 100 Watts while turning the generator at the rate you just measured. There is 5kg weight at the front of the lab. Is the force needed to turn the generator to generate 100W greater or less than the force to lift the 5kg weight?""