(10 pts] Activity Data and Calculations Volume of 6 x 9 inch bag 1.20 L Room temperature 295 k Room pressure (in atm) 1.01 atm Moles of CO, required...

Please help me solve the mass of NaHCO3 needed for the reaction (84.0g/mol) with an explanation.

(10 pts]ActivityData and CalculationsVolume of 6 x 9 inch bag1.20 LRoom temperature295 kRoom pressure (in atm)1.01 atmMoles of CO, required to inflate bagat room temperature and pressure0.05 molesBalanced equation for the reaction ofNaHCO, and CH,COOHCH3COOH + NaHC03 -> CH3COONa + H20 + CO2Mass of NaHCO; needed for thereaction (84.0 g/mol)Volume of vinegar required(0.833 M acetic acid)