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+ [((/) k/k!)*(k/k )])-1, summed for n = 0 to n = k -1 Lq = [((/)k)/(k-1)!((k-)2]*P0 L = Lq + / ( same as before) Wq = Lq/ ( same as before) W = Wq +...
+ [((/) k/k!)*(k/k )])-1, summed for n = 0 to n = k -1 Lq = [((/)k)/(k-1)!((k-)2]*P0 L = Lq + / ( same as before) Wq = Lq/ ( same as before) W = Wq + 1/ ( same as before) Pw = 1/k!*( / )k[(k)/(k-)]P0 Pn = ( / )n/n!*P0 if n < k, or Pn = ( / )n/(k!*k(n-k))*P0 if n > k Don"t worry, I will never ask you to use those formulae. It was just fun to try to type them out in Word. Q: Why doesn"t Queuing Theory say anything about costs?
