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\(magnetic field intensity, H=NI/l\) A solenoid has 500 turns of wire and a length of 0.4 meters. If a current of 2 A flows through the solenoid, calculate the magnetic field strength inside the sole
\(magnetic field intensity, H=NI/l\)
A solenoid has 500 turns of wire and a length of 0.4 meters. If a current of 2 A flows through the solenoid, calculate the magnetic field strength inside the solenoid.
Hint: Use the formula for the magnetic field inside a solenoid:
H=NI/L
Where:
- H- is the magnetic field strength (in A/m),
- N- is the number of turns,
- I-is the current (in amperes),
- L- is the length of the solenoid (in meters).
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