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QUESTION
0 ml of 0.120 m naoh is added to 565 ml of 0.200 m weak acid (ka = 8.25 × 10-5). what is the ph of the resulting buffer?
0 ml of 0.120 m naoh is added to 565 ml of 0.200 m weak acid (ka = 8.25 × 10-5). what is the ph of the resulting buffer?
