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1) The normally distributed AAA battery life is stated to be 350 days when used in a clock radio. The Big Charge Battery Company has recently...

1) The normally distributed AAA battery life is stated to be 350 days when used in a clock radio. The Big Charge Battery Company has recently modified the AAA batteries so as to extent their life. The owner of the company wanted to know if the improved batteries really did last significantly longer. A sample of 100 of the improved batteries was tested. It was discovered that the mean life was 362 days and the sample standard deviation was 10 days. The research department decided to conduct the test at the 0.05 level of significance whether the modification actually increased the life of the AAA battery. What was their decision rule? A. Reject the null hypothesis if computed z is 1.96 or greater. B. Do not reject the null hypothesis if the z test statistics is 1.96 or greater. C. Do not reject the null hypothesis if computed z is 1.65 or greater. D. Reject the null hypothesis if computed z is less than 1.96. 2) The statement that determines if the null hypothesis is rejected or not is called the A. critical value B. decision rule C. alternate hypothesis D. test statistic 3) An independent consumer testing lab preformed a statistical test on 25 type-C alkaline batteries and calculated the mean life for a particular use before they failed was 22.5 hours. The distribution of the lives approximated a normal distribution. The standard deviation of the distribution was 1.1 hours. Information on the package states that the batteries should last 24 hours. The test question was if this difference between the test statistics and the stated life of the battery was significant? The .05 significant level was selected for the test. Which is the correct statement? A. The difference indicates that the batteries are not good. B. The difference was significant; the batteries do not meet the stated length of time. C. The difference cannot be evaluated with this small of a sample. D. The difference was not significant. 4) Doi Winery has two wine shops in the neighboring towns of Seamen and Batavia. The favorite wine, as advertised, is Raspberry wine. A survey of 300 customers at the Seamen store revealed that 225 individuals preferred the Raspberry wine while 290 out of 400 in Batavia preferred the same flavor. To test the hypothesis that there was no difference in preferences in the two towns, what is the alternate hypothesis? A. µ1 ≠ µ2 B. µ1 < µ2 C. µ1 = µ2 D. µ1 > µ2 5) In classical hypothesis testing, the test statistic is to the critical value what the ________________. A. level of significance is to the test statistic B. p-value is to alpha C. test statistic is to the p-value D. critical value is to alpha 6) A statistician was setting up a hypothesis test with a level of significance dictated by upper management. However, she was concerned that the test she wished to perform might have unacceptable large possibilities of Type II error, ß. Which of the following would solve this problem? A. Convince upper management to reduce the level of significance of the test. B. Convince upper management to use a larger p-value. C. Convince upper management to use a smaller p-value. D. Convince upper management to use a larger sample. 7) You are conducting a two-tailed test of means but your software package only calculates a one-tailed p-value equal to 0.13. The actual p-value for your test is A. need a table to calculate this value. B. 0.13 C. 0.26 D. 0.065 8) A machine is set to fill the small size packages of Good and Better candies are packaged with 60 pieces of candies in each bag. Sampling results revealed: 3 bags of 61, 2 bags of 59, 1 bag of 58, and 2 bags of 62. How many degrees of freedom are there? A. 7 B. 9 C. 8 D. 1 9) When testing for differences between two means, the Behrens-Fisher problem arises when the sample populations are A. are non-normal and have unequal variances. B. normal with equal variances. C. are non-normal and have equal variances. D. are normal with unequal variances. 10) Newton’s, a tire manufacturer, wanted to set a mileage guarantee on its new Road Warrior 60 tire. A sample test of 500 tires revealed that the tire’s mileage is normally distributed with a mean of 50,000 miles and a standard deviation of 1,750 miles. The warranty on the tires is presently set at 47,500 miles. The z-test statistic result was 1.43. The manufacturer wanted to determine if the tires were exceeding the guarantee. At the .05 significant level, it was concluded that the tires are exceeding the manufacturer’s guarantee. A. The evidence does not support this decision. B. The decision needs to be delay until more data is collected. C. A decision cannot be made. D. This was the correct decision. 11) In a test for the equality of two variances (two-tailed), when the populations are normal, a 5% level of significance was used. Sample sizes were n1 = 13 and n2 = 10. The upper critical value for the test is A. =FINV(1-0.025, 13, 10). B. =FINV(0.05, 12, 9). C. =FINV(0.025, 13, 10). D. =FINV(0.025, 12, 9). 12) A recent study by College Stat Company reported a nationwide survey of college students determined that students spend 2 hours studying for each hour in the classroom. Professor Baker at State College wants to determine whether the time students spend at her college is significantly different from the national average of 2 hours. A random sample of 20 statistics students resulted in an average of 1.75 hours with a standard deviation of 0.24 hours. A t-test was conducted at the 5% level of significance. The calculated value of t was -4.03. What was Professor Baker decision? A. Reject the alternative hypothesis statement. B. Cannot make a decision at this time; more data is required. C. Reject the null hypothesis, the test statistic exceeds the critical value. D. Fail to reject the null hypothesis.

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