2M NaOCl solution is prepared by dissolving solid NaOCL in distilled water at 298K. The hydrolysis reaction OCl-(aq) + H2O(l) -- HOCl(aq) + OH-(aq)...

A 1.2M NaOCl solution is prepared by dissolving solid NaOCL in distilled water at 298K. The hydrolysis reaction OCl-(aq) + H2O(l) --> HOCl(aq) + OH-(aq) occurs.a. Calculate the value of the equilibrium constant at 298K for the hydrolysis reaction.b. Calculate the value of [OH-] in the 1.2M NaOCl solution at 298K.---So far I have the expression:K= {[HOCl][OH-]}/[OCl-]...but I don't understand how to find K if you're only given the concentration of NaOCl. Help???Thanks!