6 I 2 . _, (9.3 mls=)(75m ) = 5'" (37mlsf Its been a long time since messing with Calculator- Can't get any further 75.0m = Range 37.0mfs=Angle of

1.    An archer shoots an arrow at a m distant target, the bull's-eye of which is at same height as the release height of the arrow.

(a) At what angle must the arrow be released to hit the bull's-eye if its initial speed is m/s? (Although neglected here, the atmosphere provides significant lift to real arrows.)

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6 I2 . _, (9.3 mls=)(75m ) =5‘“ (37mlsf Its been a long timesince messing with Calculator- Can't get any further 75.0m = Range37.0mfs=Angle of Initial Speed An overhanging branch 3.50 mabove the release height of thearrow. Will the arrow go overor under the branch?