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QUESTION

# A 50.0 mL sample of phosphoric acid, H3PO4, is titrated with 42.50 mL of 0.250 M NaOH. What is the molarity of the acid? H3PO4 + 3NaOH = Na3PO4 + 3HOH

0.066"mol/l"

H_3PO_(4(aq))+3NaOH_((aq))rarrNa_3PO_(4(aq))+3H_2O_((l))

No. moles NaOH=cxxv=0.250xx0.0425=0.01

From the equation we can see that the no. moles of phosphoric acid must be 1/3 of this:

:.nH_3PO_4=0.01/3=0.0033

c=n/v

So the concentration of the H_3PO_4 is given by:

c=0.0033/0.05=0.066"mol/l"