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A ball is released, with an initial velocity of 0, on a .309 m long ramp. The ramp is set up on a table, approximately .
A ball is released, with an initial velocity of 0, on a .309 m long ramp. The ramp is set up on a table, approximately .187 m above the table, and we have to figure out where the ball will land on the floor. Here are all of the known values we have: Initial Velocity of ball = 0 m/s Length of Ramp: .309 m Angle of Ramp Relative to the Table: 42o, vertical Distance from the Floor to the Table: .750 m Variables I am trying to find:
?? = Calculated velocity(m/s)
?? = Predicted Range (m)
Equations:
v= vo + at
x= xo + vot + 1/2 at2
v2= vo2 + 2a (x-xo)
x = xo +1/2(vo+v)t
Any help would be greatly appreciated!!
