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A diode operating at 300K at a forward voltage of 0.4V carriers a current of 10mA. When voltage is changed to 0.42V the current becomes thrice.
A diode operating at 300K at a forward voltage of 0.4V carriers a current of 10mA. When voltage is changed to 0.42V the current becomes thrice. Calculate the value of reverse leakage current and Ƞ for the diode(assume VT = 26 mV).