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QUESTION
A hoop (I=MR^2) is rolling along the ground at 7.0m/s. It comes to a hill and starts going up. Assuming no losses to friction, how high does it go
A hoop (I=MR^2) is rolling along the ground at 7.0m/s. It comes to a hill and starts going up. Assuming no losses to friction, how high does it go before it stops?
Answer: 5.0 m.
Please tell me how to get h from
Mgh = 1/2Mv^2 + 1/2Iw^2.
show all steps to the equation.
