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QUESTION

# A mass of 5kg of ammonia at its boiling point is vaporized when 6.5 MJ of heat is supplied to it. Calculate the specific latent heat of vaporization of ammonia?

6.5/5 = 1.3 MJ kg^-1

The "Latent heat of vaporization" for a substance(in this case NH_3) is the heat that is required to cause a change in phase of a given mass(not specified)

We are told that 6.5 MJ caused this change at the boiling point. Which tells that ALL the heat gained = the heat needed to change in phase. Hence, 6.5 MJ IS the latent heat for vaporization of NH_3

But the question asks for "specific" latent heat, so we divide by the mass,  (6.5MJ)/(5kg) = 1.3 MJ kg^-1