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QUESTION
A particle has a charge of +1.5 C and moves from point A to point B , a distance of 0.
A particle has a charge of +1.5 μC and moves from pointAto pointB, a distance of 0.22 m. The particle experiences a constant electric force, and its motion is along the line of action of the force. The difference between the particle's electric potential energy atAandBis EPEA - EPEB = +8.8 x 10-4J.(a)Find the magnitude of the electric force that acts on the particle.(b)Find the magnitude of the electric field that the particle experiences.
