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A point D lies on the hypothenuse BC of a right triangle ABC so that AB = BD. Let P be the point on the circumcircle of triangle ADC such that angle APB is a right angle, and let L be the midpoint of
A point D lies on the hypothenuse BC of a right triangle ABC so that AB = BD. Let P be the point on the circumcircle of triangle ADC such that angle APB is a right angle, and let L be the midpoint of AD. Show that PC is perpendicular to PL.