A proton enters the electric field between two horizontal charged parallel plates with an initial speed Vo = 4.80 105 m/s at an angle Theta o = 53.0...

A proton enters the electric field between two horizontal charged parallel plates with an initial speed Vo = 4.80 × 105 m/s at an angle Theta o = 53.0° above the horizontal. The proton enters at the midpoint between the two plates, which are separated by d = 2.00 mm and charged to |∆V| = 40.0 V. Ignore gravity.

a) Use energy conservation to determine the minimum distance reached between the proton and the positive plate.

b) ) Use energy conservation to determine the impact speed Vf of the proton when it collides with the negative plate?