A sock drawer has 8 blue socks and 6 black socks. If I randomly select two socks, one at a time, what is the probability l will first get a blue sock and then, without replacing it, a black sock?

##24/91##

Calculate first the total number of permutation possible.

You select two socks so that will be:

##14*13=182##

Now you must first select a blue sock then a black sock:

You can only pick ##8## possible blue socks You can only pick ##6## possible black socks

which means that this permutation ##("blue"->"black")## have ##8*6=48## possibilities for each different blue and black sock.

express in fraction:

##48/182=24/91##

in case your curious, all possibilities have the following odds:

##("blue"->"blue")=56/182=28/91##

##("black"->"black")=30/182=15/91##

##("black"->"blue")=48/182=24/91##

##(24+24+15+28)/91=91/91##