A Travel Weekly International Air Transport Association survey asked business travelers about the purpose for their most recent business trip. 19%...

A Travel Weekly International Air Transport Association survey asked business travelers about the purpose for their most recent business trip. 19% responded that it was for an internal company visit. Suppose 950 business travelers are randomly selected.

a. What is the probability that more than 20% of the business travelers say that the reason for their most recent business trip was an internal company visit?

b. What is the probability that between 18% and 20% of the business travelers say that the reason for their most recent business trip was an internal company visit?

I submitted this and was told the calc was wrong. Please show all work.

a)

19%=internal company visit,950 business travelers,20%+ are for internal company visit

19/100*81/100 = 0.1539

20/100*80/100 = 0.2*0.8

20/100*950 = 190

(19/100*81/100=0.1539)+ (20/100*80/100=0.2*0.8)+ (20/100*950=190)

0.1539+0.16+190

190.31/100 =1.90

= 1.9

b)

950 travelers, 18% and 20%+ are for internal company visit

19/100*81/100 = 0.1539

20/100*80/100 = 0.2*0.8

20/100*950=190

(19/100*81/100=0.1539)+ (20/100*80/100=0.2*0.8)+ (20/100*950=190)

0.1539+0.16+190

190.31/100 =1.9031

= 1.9

18/100*950=190

(18/100*81/100=0.1458)+ (19/100*80/100=0.19*0.8)+ (20/100*950=190)

0.1458+0.152+190

190.29

19.31/100= .1931

= .1931