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QUESTION

# According to a report by Scarborough Research, the average monthly household cellular phone bill is \$73.

According to a report by Scarborough Research, the average monthly household cellular phone bill is \$73. Suppose local monthly household cell phone bills are normally distributed with a standard deviation of \$11.

a. What is the probability that a randomly selected monthly cell phone bill is less than \$95?

b. What is the probability that a randomly selected monthly cell phone bill is between \$62 and \$84?

Please show work. I submitted this and was told the calc was wrong:

95/0.11 Mean = 863.65

P (less than \$95) sd =\$11

0.11% of \$73, 60% of \$95*99.89-p(Y)

= 0.2*2500 + .6*6000 = \$1960

-E (U) = (0.4) (73)0.5 + (0.6) (95)0.5

=43.1

-p(Y) 2= .2(73) + .98(74) = \$95-p (U2) = 0.25(95)0.5 + 0.98(73)0.5

= 41.4%

b)

62*84 = 5208

5208-62*84-62

5208-1364 =3844

3844/0.11

34945.45/62+84

34945.45/14667

= 2.4%

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