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QUESTION

According to the American Heart Association, 19% of U.S. adults smoke cigarettes. If you were to randomly select 5 U.S. adults, what is the

According to the American Heart Association, 19% of U.S. adults

smoke cigarettes. If you

were to randomly select 5 U.S. adults, what is the probability that 4 or 5 of them would

not smoke?

I know that the answer is .7576 and i used 1-binomcdf(5,.81,3) but i don't understand why i need help explaining step by step

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