At a particular temperature, K = 4.0 x10^-7 for the reaction?

At a particular temperature, K = 4.0 x10^-7 for the reaction?At a particular temperature, K = 4.0 x10^-7 for the reactionN2O4(g) <--> 2NO2(g)In an experiment, 1.0mol N2O4(g) is placed in 10,0L vessel. Calculate the concentrations of N2O4(g) and NO2(g) when the reaction reaches equilibrium