By using Equation 1, which is 13.34 h ( 0.5 + (tan-1 (x/z)) / 180 ) mGal, show that the measured gravity anomaly of half-slab B at x = -2 km, x = 0...

By using Equation 1, which is 13.34 Δρ h π ( 0.5 + (tan-1 (x/z)) / 180 ) mGal, show that the measured gravity anomaly ofhalf-slab B at x = -2 km, x = 0 km and x = 2 km withΔρ = +0.43 g/cm3h = 10 kmz = 12.4 kmare +80.9 mGal, +90.1 mGal and +99.3 mGal respectively.

Gravity anomaly of half slab is given by the equation- x13.34∆p h π 0.5 + tan − 1 / 180 z Also given ∆p = 0.43 g / cm 3 , h = 10km , z = 12.4kmTo find the gravity anamoly at x = −2km...