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calculate the maximum number of moles and grams of H2S that can form when 208.5g of aluminum sulfide reacts with 175.2g of water: Al 2 S 3 +6H 2 O =
calculate the maximum number of moles and grams of H2S that can form when 208.5g of aluminum sulfide reacts with 175.2g of water:
Al2S3+6H2O = 2Al(OH)3+3H2S
___?___ mol H2S
___?___ g H2S
What mass of the excess reactant remains?
___?___ g excess reactantÂ
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