Answered You can hire a professional tutor to get the answer.

QUESTION

Class: Chemical analysisHello, this was a very difficult lab

Lab 5. (5). A steel sample (0.5000 g) treated the same way as done in Lab 5 was diluted into 500 mLvolumetric flask. What is the amount (g/mL) of steel in the solution? Lab 6. (10) The amount of Mn in steel sample from Lab 5 was analyzed using AAS. A calibration curve wasprepared wherein different volume of stock solution (5 mM) was used and then diluted with 0.05 M nitric acidto 50 mL. Sun 1 the information missing in the _iven table and show sam- le calculation for one entry. Vol of 5 mM used Concentation of Mn1.00 0.100 —— 0.150 —— 0.200—— 0.250—— 0.300 (5) Determine the equation of the line: (10) The sample from Lab 5 gave a reading of 0.220. What is the concentration of Mn in the given sample? Lab 7. (10). For the analysis of sample from Lab 5, 3 beakers containing 25 mL of the sample from Lab 5 waseach added with 5 mL phosphoric acid and then treated differently (some added with K104 while one wasadded with 5 mL of 2 mM Mn standard) before being transferred into a 50—mL volumetric flask and then addedwith water to the 50 mL mark. The absorbance reading afier zeroing with the blank is 0.700 for the sample withadded standard and 0.300 for just the sample. Determine the concentration of the Mn in the original sample.

Show more
LEARN MORE EFFECTIVELY AND GET BETTER GRADES!
Ask a Question