Cnnsider the cumbustlun of propane 935, CaHatg} + 502th r Sci-32(9) + 4H20} amquot; = 4,220 karnnl How much heat can he obtained by burn1ng 13.0

Can you please help me with this question. I understand that I am supposed to first convert from pounds to grams then divide the answer by the molar mass and lastly multiply the answer by the given heat in KJ to get the final answer. However, the answer I got was wrong so I guess that either my conversions were wrong or I completely misunderstood the entire question.