Complete the following questions please.

* 3/x ** * **** * ***** Write *** ***** or ****** ** the ******** **** **** a *********** zero ***** *** *** ************ ** the ********** *** ******** *** + * * **** * 28/9 ** **** *** ************* * and 3x ** **** *** ************ ** **** ** *** these denominators ***** ** **** *** solve *** xSetting *** denominator * ***** ** zero: * * ******** *** denominator ** ***** ** ***** ** * x = *** * * ********** *** restriction ** the ******** ** * ≠ ** ****** ** ***** ** zero) ***** ** ***** **** *** of *** ************ ******* ******* the restrictions ** **** ***** the ************* ***** solve *** equation 3/x * * * 2/3x * **** considering *** *********** * *** ********* the ****** ******** ** *** least ****** *********** ***** ** ** ** ********* the ************ * ***** * ** * 3 * ** * ****** + ** * ***************** *** *********** + ** * * + ************** the ******** * *** * * * ****** = *********** **** ***** ** -19:x = *** * ************** *** ********** * 21/19Therefore the ******** ** *** ******** *********** the *********** * *** is * * 21/19  a The restrictions ** *** variable *** x(Use * comma ** ******** ******* ** needed)To ********* *** ************ ** *** variable x in the ******** 3/x + * * 2/3x + **** we **** to ******** *** ****** **** ***** **** the ************ ***** to ******* ************ ** *** equation *** x *** 3x To **** the ************ we *** ***** ************ ***** ** **** and ***** *** ***** * 3x * ************** the ****** equation ** ********* * 0x * 0/3x * 0 Therefore *** ************ on the ******** * *** x * 0b ***** *** equation Select *** ******* ****** ***** *** if ********* **** in *** ****** *** ** complete your ******** solve the ******** *** * * * **** + 28/9 let's ***** ******** ** ** finding * common denominator *** *** ********* *** ***** ****** *********** ***** is **************** **** **** ** ** ** ******** * ***** * ** * 3 * 9x * ****** + ** * ******************* *** ************* * 27x * 6x * 28x + ************* like terms: 27 + *** = 34x * 84 Rearranging the ************* + *** * *** * ******* * ** * *************** ** from **** *********** = 57 Dividing by -7: x * -57/7 Simplifying *** ************ * ******************* the ******** ** *** equation ** * = ***** ** ************* * * ********** ****** a 2 Compute *** ************ Then determine *** number and **** of solutions of the ***** equation *** * ** - 7 * ***** ** *** discriminant?(Simplify **** ************* *** ******** that ********* the ****** *** **** ** ********* ** the ********* ********* There *** two unequal real ********** ***** is one **** ********* There *** ** infinite ****** ** **** ********** ***** *** two ********* solutions  The ***** ******** ** x^2 * 2x * 7 * ***** ********* the ****** *** type of ********* ** **** ** ********* *** ************ ***** ** ***** ** *** ********************** *** * *** * ******* this equation * = * * * ** *** * * **************** *** ****** **** the *********** * ****** - ********* * + *** ******* ************ ** ******* let's ******* *** ****** and **** ** solutions based ** *** ***************** the ************ is positive ** **** 0) **** the ******** *** *** ******** real solutionsIf the discriminant ** **** ** * ** then the ******** has one **** ********** *** discriminant ** negative ** **** ** then the equation has *** ***************** **************** *** ************ ** * * ** ***** ** ******** the ******* choice ********** *** two ******* real solutions 3 Solve *** ******** by *** ****** ** **** ******************* * ******* * ** *********** ******** *** is * } ******** ** exact answer ***** ******** as ****** *** * comma ** ******** ******* ** ************ ***** equation ** ************* = ******* * ************ simplify the equation ***** factor the ************* x^2 * 3x * ** * (x * 6)(x - ** *** * 36 = ** * 6)(x * 6)Now ** *** ******* *** ******** **** ******** ************* ***** * **** * 3)) = **** * ** * ***** * **** * ***** find * ****** *********** ******** **** **** ** ** * **** * *** [(x * 6)(x * ******* * **** * 3)] * *** - **** * ****** - ** * 2/[(x * 6)(x * 6)]Canceling out ****** ******** **** * 3) * * + **** * 6)Multiplying ******* ** ** - 3)(x * 6) ** ********* *** fractions: (x * **** * ** * (x - **** * 6) * 2(x - 3)Expanding *** ************ *** * ** * ** = *** * 5xSubtracting *** *** 5x **** both ****** ** * ** * 0Adding ** ** **** sides: 3x = ********** by 3: x * 6Hence *** solution to the ******** ** * = ********** ***** the equation ** ********* ***** *** - ****** ******** *** ** * ******** * ***** ** ******** ******* ** ********** quadratic equation *** ** factored as ************* * ** * * * ****** the ******* *********** ** 16 ** *** ***** ** ********* out the ****** ****** ** ******** * x - ** * 0Now ** **** ** **** two binomials **** multiply ** **** **** * x * * Let's write *** middle **** ** *** *** of *** ***** **** ******** ** **** *** *** * ** and *** to **** *** *********** ** x ***** ** ******** * 3x * ** * 3) * 0Grouping *** ***** ** ************ * *** * *** * 3)) * ********** out ****** ***** **** each *********** - ** * (4x * 3) * **** ** notice that *** * ** ******* ** * ****** ****** ** both terms ********* ** *** we ******* * 3)(4x * 1) * 0Setting each ****** ***** ** ******* * 3 * ** ** * 1 * ******** *** x in **** equation:4x * * * 4x * * * * ***** * * * 4x * ** * * ************* the solution set ** *** ******** 16x^2 * ** * 3 = *** x * 3/4 ************** 55 **** *** values ** * satisfying *** following ************ * (x-4) /5 ** ******* /6 and ** *** * ******* the correct choice ***** *** **** ** any ****** ***** ****** **** ****** A *** solution *** ** * * ********* **** ******** There *** no ************* **** all ****** of * ********** the ***** ********** ** **** ** ***** *** ******** y1 * ** * * ***** ** * (x * **** and ** = (x * ***************** the ***** *********** *** y1 *** ** **** *** *********** * **** * ** * ***** = 1To ******** *** ******** ***** **** a common denominator for the ********* ***** ** 30:6(x - 4)/30 - *** * ****** * ********** *** numerators:(6x * ****** * *** * ****** * 1Combining *** ************* * ** * 24 * ****** = 1Simplifying:(x * ****** = **** ***** ******* x ** multiplying **** ***** ** the equation ** **** * ** = ************* ** from **** ******* = ** - *** * ************ the ******** *** ** the ******** y1 - ** * 1 is: x * ****** correct ****** *** * *** ******** set ** {-11}  Question ****** the ******** ** *** method of your choice **** ** *** ** ***** ******** *** ** ******* ** ***** ****** ***** ******** ** needed *** * ***** ** ******** ******* ** *********** ***** *** equation (5x + **** * 1) * 2 ** can *** *** ************ ******** ** ****** *** **** **** of *** ************* * ** + 4x * * * 2Combining **** terms:5x^2 * 9x * * = 2Now let's ********* *** ******** to ***** it to *** **** ** * ********* ************* * ** + 4 * * * ***************** * ** * * = *** solve this ********* ******** ** *** *** the ********* ******* ***** ****** that *** ** ******** ** *** **** **** * bx * * * *** solutions are ***** **** * *** ** ******* - 4ac)) / ******* *** equation a * * b * * *** * * 2 ************ ***** values **** *** ********* formula:x * ***** ** √((9)^2 * 4(5)(2))) * (2(5))Simplifying ********* * (-9 ** ****** - **** / ** * * *** ** ****** * *********** the solutions ** the ******** (5x * 4)(x * 1) * * ***** * *** + ****** * ** *** * ****** * ***** ******** set is **** + ****** * ** (-9 * ****** * ************* ****** the ********* ******** ***** *** ********* ******* **************** ******** set ** * }•(Type ** exact ****** ***** radicals as needed Use * ***** ** ******** ******* as *********** ***** *** ******** **** - *** * * = ***** *** ********* ******* ***** ******** *** ************ of *** ********* ********* a * * * = *** and * = ***** ********* formula states **** *** ** ******** ** *** **** **** + ** + * * *** ********* *** given by:x * *** ± ******* - ***** * **************** *** ****** into *** ********* * ******* ** *********** * ********** * ***************** ********* * *** ± √(121 * *** * 4 * * (11 ** √(129)) * 4Therefore *** ********* ** *** equation **** * *** * * * using *** quadratic ******* ***** = *** + ******* * * *** - √129) / 4The ******** set is **** * √129) / 4 *** * ******* / 4} Question **** following ******** ******** *** denominators that ******* ********* *** this ********* ***** the ***** or ****** of *** ******** **** **** * *********** **** ***** are the ************ ** *** variableb Keeping *** ************ in mind ***** *** equation(9x/(x+1)) ** ***** + ******** ** *** value or ****** ** the ******** that ***** *** denominators zero?x=(Simplify your ****** *** * ***** to ******** ******* ** needed)Solve *** ******** Select *** correct ****** below *** ** necessary **** ** *** ****** *** ** ******** **** choiceThe ******** *** ** { } (Simplify **** answer)There is ** *********** *** ***** ** ****** ** *** ******** **** **** *** ************ zero *** ***** ** *** equation * * * = ******** * * * * 0: x = -1Therefore *** ***** of the variable **** makes the *********** **** ** * = *** Now ***** solve *** equation ********** * * * 9/(x + ** ******* *** *********** * *** ** ** mindMultiplying ******* ** ** * ** ** eliminate *** ************* ** * ** * 9/(x * ***** + 1)Expanding *** simplifying: ** = *** + ** - 9Distributing and ******* ************ ** * 6x * * * 9Combining **** terms: ** * 6x = -3Simplifying: 3x = ********** ** ** * * ********* this ******** ******** *** restriction * ≠ ** as it makes the *********** **** ********* ***** ** ** ***** solution that ********* *** ***** ******** *** ************** ******* choice *** ***** ** ** solution *** ******** *** is ************** ****** *** ******** ** *** ****** **** property *** * ** ** * ***** solution set ** * * •(Type an exact ****** using ******** as ****** Use * comma ** ******** answers as ****** ******** **** *********** ***** *** ******** *** * **** * ** ***** *** ****** root ******** ***** ****** ***** ************ **** ***** ** *** ******** by * ** isolate *** ******* ***** (x * **** * ****** *** ****** **** of **** sides ** *** equation: √[(x * 3)^2] * *************** that **** ****** the ****** root we consider **** *** positive *** ******** ****** ************* *** ****** root *********** x * * * ±√(9 * ** x * 3 * ±3√5Subtract * **** **** ***** ** the equation: * = ** ** ************** *** solution *** ** the ******** 2(x + **** * ** using the square **** property *** * = ** + ***** ** * *************** 10Solve the ******** ** **** ** ***** your proposed ******** ** ************ ** *** *** ******** ** *** original ******** *** *** - *** * ********** the ******* ****** ***** *** ** ********* **** ** *** ****** *** to complete your choiceThe ******** *** ** ************ solution *** ** *** **** ************ ** ** solution To ***** *** ******** ** * *** * *** = ** let's ******** *** ***** for x:First distribute the ******** ***** ** * ** * 10 * ********* **** ****** 6x * ** * ********** ** **** **** sides: ** * ******** **** ***** ** ** x = ********** *** ******** ******** is * = 6To verify ** *** ******** is ******* ** ********** x = * **** into *** ******** ************* * ***** * 10) * ** 48 - *** * *** * 46 ** * 2 * ** 46 * ***** ******** holds **** which ******** **** * = * ** the ******* *********** correct ****** **** * The ******** *** ** ***