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Data Sheet: Activity - Genetics All Content is Copyright Protected and May NOT Be Posted or Shared Outside Of The Classroom Name Course Date Activity Data Code Procedure I - Part A
Data Sheet: Activity - Genetics
All Content is Copyright Protected and May NOT Be Posted or Shared Outside Of The Classroom
Name
Course
Date
Activity Data Code
Procedure I - Part A - Baby bugs when parents are BB and bb
Data Table - Enter your Baby Bug Counts
BB Baby Bug
Count
Bb Baby Bug
Count
bb Baby Bug
Count
Percentage Tables - Enter the Baby Bug percentages
Tip: Baby Bug Percentage = 100% ´ (Baby Bug Count) / (Total Number of Baby Bugs)
BB Baby Bug
Percentage
Bb Baby Bug
Percentage
bb Baby Bug
Percentage
Tip: Blue Rimmed Baby Bug Percentage = BB Baby Bug Percent + Bb Baby Bug Percent
Blue Rimmed Baby Bug
Percentage
Yellow Rimmed Baby Bug
Percentage
Observations and Questions
[1] Complete the Punnett square below when the parents are BB and bb.
Punnett Square
Male
Female
Alleles/Genes
B
B
[2] Describe your baby bug results from this data run in terms of genotypes and phenotypes.
[3] Why are there no BB baby bugs or bb baby bugs from this data run?
[4] Do the results for the allele distributions confirm the entries in your Punnett Square? Please explain.
[5] What evidence from this data run supports the hypothesis that the B allele is heterozygous dominant? Explain your reasoning.
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**** ****** Activity * *********** ******* is Copyright Protected and *** *** ** ****** ** Shared Outside ** *** ***************************************** **** *************** * * Part * * **** **** **** ******* *** ** *** bb Data ***** * Enter your **** *** ************ Baby ********** **** ********** **** ********************** Tables * Enter *** **** *** ***************** **** *** ********** * **** ** ***** *** ****** * (Total Number ** **** ********* **** *************** Baby *************** **** *************************** Blue Rimmed Baby *** ********** * ** **** Bug ******* * ** Baby *** Percent Blue Rimmed **** ******************* ****** **** *************************************** and Questions [1] ******** *** ******* ****** below **** *** ******* are BB *** *********** **************************************************** ******** **** **** bug results **** **** **** *** in ***** of ********* and phenotypes The baby *** ******* ** terms ** ********* is **** *** *** heterozygous ** ** terms of phenotypes **** *** *** **** *** to *** ******** * allele [3] *** *** ***** no ** **** bugs ** ** baby **** **** this data ********* Punnett ****** ***** the ******* ** ***** ****** **** ********** ******* ** **** **** run [4] ** *** ******* *** *** ****** ************* ******* *** ******* ** **** ******* ******* Please ******* *** *** ******* ****** ******** *** ****** distributions because ***** are no ** baby bugs ** ** baby **** **** ** **** ***************** **** ******** from **** **** *** ******** *** hypothesis **** *** * ****** ** heterozygous dominant? ******* **** ************** ******** **** **** **** run ** *** **** ************ ****** with the ************** **** color ** *** * ****** **** shows **** ** ** a ************ ******** allele Procedure * * Part * * **** bugs **** ******* *** ** and Bb Data Table * ***** **** **** Bug Counts **** each data ************** **** ********** **** ********** **** ******************************************************* Averages ***** - Enter **** ******* Baby Bug Counts Tip: ** Baby *** Count Average * *** of ** **** *** ****** * ****** of Data ******** **** ******** ********* **** ******** ********* **** BugCount ************************** ****** * ***** *** Baby *** ***************** **** *** Percent = 100% ´ (Baby Bug Count ******** / ****** Number ** **** ********* **** BugPercentageBb Baby *************** **** BugPercentage53%47%0% Tip: **** Rimmed **** *** ********** = BB Baby *** ******* + Bb **** Bug ************* ****** **** ******************* ****** **** ********************************* *** **************** ******** the ******* square ***** when the ******* *** ** *** *********** ************************************************** ***** **** Punnett ****** calculate the ******** ********** of **** Rimmed **** Bugs *** ****** Rimmed Baby **** Show **** work How ** your ********** ***** ******* ******* **** *** ******* ****** ************* ******* ***** ******** ******* **** *********** ******** ********** ** Blue Rimmed **** Bugs ** 100% *** ** Yellow Rimmed Baby Bugs The percentage table ******* *** ******* **** my ******* ****** ************ ******* BB *** ** ********* share the same ********* so there ** * **** of a child being **** **** **** phenotype [8] *** ** ** *** ******** **** **** *** **** ********** ******* your ********** *** ******** **** **** ** be have *** **** ******** *** ******** data Also ** **** **** you *** *** have *** *********** *** **** set ** parents is ** ******** ** **** conclusions ***** *** ******** ****** **** ********* *** *********** *** ** why **** *** counts **** *** ** **** BB ** ** **** **** ** part of **** discussion No ** ** *** ******** to draw conclusions about *** ******** counts **** the ********** because **** wont ** ********** “accurate” *** **** *** * ** **** * BB * ** *** bb *** ***** is ***** off * ********** *** * *********** ******* ** *** ******** **** blue rimmed *** 0% ****** ****** but *** many ** and ****** ****** *** ****** ** ***** **** **** ***** are ***************** I - **** C * **** **** **** parents *** ** *** Bb Data ***** - Enter your **** Bug Counts from each **** run DataRunBB **** BugCountBb **** BugCountbb **** ******************************************************* ******** ***** - Enter your ******* Baby *** ************ BB **** Bug Count ******* * Sum ** ** **** Bug ****** / ****** ** Data ******** Baby ******** ********* **** BugCount ********* Baby ******** ************************** ****** * Enter the **** *** ***************** **** Bug ******* * **** ** ***** *** ***** ******** * ****** Number of **** Bugs) BB **** BugPercentageBb Baby *************** Baby *************************** **** ****** **** *** ********** * BB Baby *** ******* * ** Baby *** Percent Blue ****** **** BugPercentageYellow ****** **** BugPercentage47%53% Observations *** *************** ******** *** ******* ****** ***** **** *** parents are ** *** *********** SquareMale FemaleAlleles/GenesBbbBbbbbBbbb [11] Using **** Punnett ****** ********* *** ******** ********** ** **** ****** **** **** *** ****** ****** **** **** Show your **** How ** **** ********** ***** ******* ******* with *** Punnett ****** calculations? ******* ***** ******** ******* your answer *** ***** ** **** rimmed baby **** *** *** would be ****** rimmed baby **** *** ******* square *********** is similar ** *** ********** ***** results *** ********** ***** ***** 47% **** ****** **** bugs because there *** ** Bb **** *** BB **** ** *** ****** ****** baby **** *** ******* ***** **** ** ** bugs [12] For **** *** ** parents ** it ******** ** draw conclusions ***** *** ******** counts **** ********* *** *********** *** ** *** not? *** counts **** *** of **** ** ** ** **** **** as **** ** **** ************** ** ** not ******** to **** *********** ***** *** genotype ****** **** the phenotypes because **** will *** be completely ************** *** **** run * ** **** ** 5 ** *** * bb *** ***** ** based *** B ********** *** b *********** ******* ** *** conclude *** **** ****** and 50% ****** rimmed *** *** many ** Bb *** ****** ****** *** there? Procedure * * **** * * **** bugs **** ******* *** ** and ******** Table - ***** **** **** *** ****** **** **** **** ************** **** ********** **** ********** Baby ******************************************************* Averages ***** - Enter **** average **** Bug ************ ** **** *** ***** ******* = Sum ** ** **** *** ****** * ****** ** Data ******** Baby BugCount ********* **** ******** ********* **** ******** Average195229 Percentage ****** * ***** *** **** *** ***************** **** *** Percent * **** ´ ***** Bug ***** ******** * ****** ****** ** **** Bugs) BB **** *************** **** *************** Baby **************************** **** ****** Baby *** Percentage = ** Baby *** ******* + ** **** Bug ************* ****** Baby ******************* ****** **** ************************************* *** *************** Complete *** ******* ****** below **** *** ******* *** ** *** Bb Punnett ***************************************************** ***** your Punnett ****** ********* the ******** ********** ** **** Rimmed Baby **** *** ****** Rimmed **** Bugs **** **** **** *** ** **** ********** ***** ******* compare **** *** ******* ****** ************* ******* ***** ******** ******* **** *********** ***** be Blue ****** **** **** *** *** ****** ****** **** **** ******* to *** ********** ***** results The percentage ***** ******* show *** blue **** bugs *** 29% ****** ****** baby **** *** ***** Bb= *** blue baby ****** **** *** ** *** 29 ****** ****** **** ********************* *** ** ** Bb ******* ******* *** *** genotype ****** confirm *** counts for *** ********** ** the ******* ** ******** Use ****** **** *** of **** ** ** ** **** **** ** part of **** **************** data *** 8 * ** * ** * ** **** ** ****** ******* *** same ** the ********** ***** ********* *** *************** of ***** ***** ** ******* *** ******** ****** ******* *** counts *** the ********** ** the ******* ******* B ** ******** *** * is ********* **** ******* in more **** ****** **** **** **** ****** ****** **** **** ** *** ************************ II * **** * * *** ********** changes **** there ** * ******** ********** *** **** ****** ********** ***** * Enter **** Final Bug Counts BB BugCountBb ********** ************************ ****** * ***** *** ***** Bug percentages Tip: *** **** Percentage * 100% ** **** **** Count) / (Total Number ** ********* BugPercentageBb *************** *************************** Blue ****** **** *** ********** * ** *** Percent * ** Bug ************* Rimmed ******************* ****** ********************************* *** *************** ******** *** bug population ****** ******* ****** **** **** *** ** terms ** genotypes *** phenotypes The baby *** ******* ** ***** ** genotypes is they *** are ********** ** In terms ** ********** **** are *** **** *** to the ******** * ************** ** **** results ******* anything ***** what the *********** ** this ********** might be ** some ******* ***** ** *** ******* ****** your answer Only blue rimmed **** **** because there ** no ********* ****** **** **** ******** ****** **** The population ***** **** ****** only ******* of **** ****** baby bugs ******* ** ************** ***** ** *** ******* ******** ********** *** the ************** ******** ** ******* *** ****** *** ********** ********* composition ***** Under *** ********** *** ** ** *** ******* ** Formulas ****** *** Calculations ******* *** the ******* ****** Using *** ************** ******** **** ** **** * *** **** * ***** the initial ******** ********** for this **** ***** *** q=5 2) ************ ********************* ** this ********** consistent **** *** expectations ** the ************** ***** **** ** is this ********** ******* ***** ***** the ********** tab ** to *** ******* ** Formulas ****** for ************ section *** the example ****** Using *** ************** ******** **** do **** * and Step 4 *** this **** ***** ******** Blue =10/20=5=50% Observed ****** ************** **** *** ********** **** ********* *** Yellow — ********** **** ********* ************** **** population ** *** consistent with the expectations ** the ************** **************** ** * **** * * *** ********** ******* when ***** is * breeding preference for ****** ****** ********** ***** * ***** your Final *** Counts BB ********** BugCountbb ************************ ****** - Enter *** ***** Bug ***************** Bug Type ********** * **** ** **** **** ****** / (Total ****** ** ********* *************** *************** ************************** Blue ****** **** *** ********** * ** Bug ******* * ** *** Percent Blue Rimmed ******************* Rimmed ********************************* *** *************** Describe *** bug ********** ****** results ****** this **** run ** terms of genotypes *** *************** **** rimmed bugs will remain same in appearance *** ***** genotypes could ** ** ** ** *** ****** ****** **** **** ****** only when **** recessive alleles ** *** ******* **** causes the ********** in genotype *** ********* ********** *** both *** bugs [21] ** **** ********** ********** **** *** expectations of *** ************** model **** ** is **** ********** stable? ***** Under *** Background *** ** ** *** ******* of ******** ****** for ************ ******* *** *** example ****** ***** *** Hardy-Weinberg Equation **** ** **** * and Step 4 *** **** **** ******* ******** ***** ********** ******** ******* *************** **** *** ********** **** ********* *** ****** *** ********** **** ********* ************** This ********** ** ********** **** *** ************ ** *** Hardy-Weinberg ************* ******* **** your ******** above ********* about the ************* of *** ************** ******** ** **** ********** ***** *********** if any ** *** Hardy-Weinberg criteria *** ************ ******* the ************** criteria ****** ******* **** **** ********** * ** *** *** ******** **** the ************** ******** violated Procedure II * **** * * *** Population changes **** ***** ** *** * rim-color ******** ********** *** **** ******** ************ Table * Enter **** ***** Bug ************ BugCountBb ********** *********************** Tables * ***** the ***** *** ***************** *** Type ********** * **** ** (Bug **** ****** / ****** ****** ** ********* *************** *************** BugPercentage25%45%30% Tip: **** ****** Baby *** Percentage * ** Bug ******* + ** *** ************* Rimmed ******************* ****** *********************************** *** Questions [23] ******** *** bug population ****** ******* ****** **** **** run in ***** of ********* *** ************* **** ****** **** **** ****** same ** ********** but their genotypes ***** ** ** or ** The ****** ****** **** **** ****** **** **** both ********* ******* bb *** ******* **** causes *** difference ** ******** and ********* ********** *** **** *** ************ Is this ********** consistent **** the ************ ** *** ************** ***** that ** is **** ********** ******* ***** ***** the ********** *** ** ** *** Summary of Formulas ****** *** ************ section *** *** ******* titled ***** *** Hardy-Weinberg ******** then ** **** 3 *** **** 4 for this data ******* Observed Blue: *********** ******** ******* 6/20=3=30% 4) **** *** ********** **** observed: 70% Yellow — predicted: **** observed: 30%Conclusion: **** ********** ** ********** with the ************ ** the Hardy-Weinberg *********** ******* **** **** ******** ***** ********* ***** *** ************* ** *** ************** criteria ** **** population ***** *********** if any ** *** ************** ******** *** ************ believe the Hardy-Weinberg ******** ****** ******* **** this ********** * do *** *** ******** that *** Hardy-Weinberg criteria violated Note: *** ***** ***** ******* ** ******* and ********* Procedure ** * Part * **** **** **** ****** ********** **** ********** **** ****** *** ***** *** ******* process ********* ******* ***** *** ***** *** when *** should **** your ******* and answers to the questions ********* *******