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# DS = Gauss Law is exact and always true. The inner sphere carries a charge Q1, and the spherical shell carries a charge Q2, such that Q2 = -3Q1. How

DS = Gauss Law is exact and always true. The inner sphere carries a charge Q1, and the spherical shell carries a charge Q2, such that Q2 = -3Q1. How is the charge distributed on the sphere? How is the charge distributed on the spherical shell? What is the electric field at r < R1? Between R1 and R2? At r > R2? What happens when you connect the two spheres with a wire? (What are the charges?) How is the charge distributed on the sphere? Q1 * The electric field inside a conductor is zero. How is the charge distributed on the spherical shell? * The electric field inside the conducting shell is zero. (B) There can be no net charge inside the conductor, therefore the inner surface of the shell must carry a net charge of -Q1, and the outer surface must carry the charge +Q1 + Q2, so that the net charge on the shell equals Q2. Q2 + Q1 What is the Electric Field at r < R1? Between R1 and R2? At r > R2?