E = z / 2 A sample of the reading scores of 35 fifth-graders has a mean of 82. The standard deviation of the sample is 15.

E = z / 2 A sample of the reading scores of 35 fifth-graders has a mean of 82. The standard deviation of the sample is 15. a. Find the 95% confidence interval of the mean reading scores of all fifthgraders. B. Find the 99% confidence interval of the mean reading scores of all fifthgraders. C. Which interval is larger?