Finally, I estimated Model 4, which uses the natural log of the price, ln(Price), for the response variable: The regression equation is lnPrice =...

Finally, I estimated Model 4, which uses the natural log of the price, ln(Price), for the response variable:The regression equation islnPrice = 9.80 - 0.000008 Mileage + 0.105 Liter + 0.328 Cruise - 0.0550 Sound + 0.0531 Leather - 0.350 Cylinder_4          - 0.418 Cylinder_6Predictor          Coef     SE Coef      T      PConstant         9.7957      0.1617  60.60  0.000Mileage     -0.00000760  0.00000120  -6.34  0.000Liter           0.10499     0.03140   3.34  0.001Cruise          0.32772     0.02478  13.23  0.000Sound          -0.05502     0.02172  -2.53  0.012Leather         0.05306     0.02341   2.27  0.024Cylinder_4     -0.34984     0.09961  -3.51  0.000Cylinder_6     -0.41772     0.05714  -7.31  0.000S = 0.277882   R-Sq = 54.5%   R-Sq(adj) = 54.1%

What is the predicted ln(Price) for a car that has 8000 miles, 2 liters, no cruise, no sound, no leather, and 8 cylinders? Use four decimal places.