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find the least value of n for which 1+3+3^2+....+
find the least value of n for which 1+3+3^2+....+3^n-1>1000
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******* * * ******* ** a ********* *********** ** common ***** *** which ** ******** ** dividing *** ** ***** *** ***** term is a=1 *** ** a GP = * ((r^n -1)/(r-1))Substituting *** * *** r *** we equate ** 10001×((3^n-1)/(3-1))=1000(3^n-1)/2=10003^n-1 * ******* * 2001 the ***** ***** ** ****** log ** ***** sideLog3^n * ***************************** ****** * ************ *** least ******* * **** ** *******