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QUESTION

Find the ph of a 0.135 M aqueous solution of periodic acid (HI04), for which Ka =2.3 x10-2.

Find the ph of a 0.135 M aqueous solution of periodic acid (HI04), for which Ka =2.3 x10-2.

PH = PKa + Log CNow,ka =2.3 * 10-2So Pka = -log (2.3*10-2)= 2-log(2.3)=1.638Now,Concentration = 0.135 MPutting all valuesPH = 1.638 + log(0.135) = 0.768
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