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# Find the surface area generated when the function f(x)=[sqrt(x)] on the interval [2,6] is revolved about the x-axis

Find the surface area generated when the function f(x)=[sqrt(x)] on the interval [2,6] is revolved about the x-axis

Find the surface area generated when the function f(x)=[sqrt(x)] on the interval [2,6] isrevolved about the x-axisSol:Since y' = (1/2)x^(-1/2),√(1 + (y')^2) = √(1 + 4/x).Thus, the surface...