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Finding molarity: PLEASE HELP ME
FINDING MOLARITY:
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75.0 mL of an AgNO3 solution reacts with enough Cu to produce 0.250g Ag by single displacement. What is the molarity of the initial AgNO3 solution if Cu(NO3)2 is the other product?
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**** Answer
** *** ***** ** ***** **** *** ********* *** ** * of ******** that only *** *** grams ** ** **
****** ** **** ****** *** **** ******* ** ***** * 100 g/ml so ***
grams = 750 ** ** ******** **** ***** using
molar
***** 0250 * ** * *****
g/mol 0002318 ***** *** find molarity: 0002318 ***** ** *
*****
****** = *****
Molar *** ***** ***** Ag+ * = 00309 ***** *****
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Tutor has posted answer for $60.00. See answer's preview
** *** ***** ** start **** *** ********* *** ** * of solution that only *** 025 ***** ** ***
is ****** to have ****** *** **** density ** ***** * *** g/ml
so 750 grams = *** ml of *********
****
***** ***** ***** ****** ****
* ** * ***** ***** 0002318 moles **** ****
molarity:
******* moles
** * ***** ****** * ***** Molar **** ***** *****
***
= * ***** ***** *****
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Tutor has posted answer for $50.00. See answer's preview
** are ***** to ***** with the ********* *** ** g ** ******** **** only has *** ***** of ***
** ****** ** **** nearly *** **** ******* as ***** * *** *****
so *** ***** * *** ml ** *********
find
***** using ***** mass: ****
g ** * ***** g/mol ******* ***** **** find
molarity:
******* *****
** * 00750 ****** = 00309 ***** **** ***** Molar
***
* * ***** ***** *****
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- ANSWER
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Tutor has posted answer for $48.00. See answer's preview
******* *** ******** is weight×1000÷molar ************
***** molarity **********************
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Tutor has posted answer for $48.00. See answer's preview
******* for molarity ** ******************* ************
Agno3 ******** **********************
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Tutor has posted answer for $5.00. See answer's preview
*** ******** reaction ** 2AgNO3(aq) + ** *** =Cu(NO3)2(aq) * *******
*****
** ****** ***** **** its **** ** **** **** be ****************
mass
************* =0002317643
******
Because
*****
*** enough
copper
**** *** ** *** ****** ******* reacted hence **** ***** being *** ****
******
******* ***** that reacted ** equal ** ********** moles ************* *** * =1000ml ************************ ****
*******
*********
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Tutor has posted answer for $60.00. See answer's preview
**** the attached ****
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Tutor has posted answer for $60.00. See answer's preview
**** ** your answer Please ***** **