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QUESTION

# For a particular redox reaction SO3 2- is oxidized to SO4 2- and Cu 2+ is reduced to Cu + . What would the complete and balance equation for this reaction in basic solution?

SO_3^(2-) + Cu^(2+)+ 2HO^(-) rarr SO_4^(2-) +Cu(s) + H_2O(l)

When basic conditions are specified, it is normally best to balance the equations in acid, and then modify the final equations.

"Sulfur (IV+)" rarr "Sulfur(VI+)":

SO_3^(2-) + H_2Orarr SO_4^(2-) +2H^(+) + 2e^(-)

For basic conditions, add 2xxHO^- to EACH side (HO^(-) + H^(+)rarrH_2O):

SO_3^(2-) + 2HO^(-) rarr SO_4^(2-) +H_2O + 2e^(-)

"Copper (II+)" rarr "Copper (0)":

Cu^(2+) + 2e^(-) rarr Cu

You have asked another such question recently. Do you follow the method of doing redox equations?