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QUESTION
Given a random sample X=(X1,.,Xn) where Xi ~ N(mu, sigma^2) determine the probability distribution of the sample mean X_bar = 1/n * [X1 + . + Xn].
Given a random sample X=(X1,...,Xn) where Xi ~ N(mu, sigma^2) determine the probability distribution of the sample mean X_bar = 1/n * [X1 + ... + Xn]. (Stating the result without a formal proof is sufficient)
