Hi can someone help me with these Mechanical Eng question.i am super lost. sorryand thank you in advance

AutoSave (. Off)Tutorial6.1 Newton's First Law(1) (1) - Protected View - Saved to this PCNUR ATIKA BTE ZULKORNAIN NAXFileHomeInsertDesignLayoutReferencesMailingsReviewViewHelpSearchShareCommentsName:Std No.:Group:Name:Std No.:GroupMechanical Engineering Fundamentals38MEFMechanical Engineering Fundamentals38MEFNGEE ANN POLYTECHNIC4. Block A of mass 80 kg is connected to Block B of unknown mass via a light cable, whichSCHOOL OF ENGINEERINGruns over a light and smooth pulley. Determine the tension, T, in the cable and the mass ofMECHANICAL ENGINEERING FUNDAMENTALSBlock B, Mb, such that Block A will have an impending motion up the inclined plane.I = 379 NTutorial 6.1: Newton's First Law (Equilibrium of a Particle)Mo = 38.6 kg1. Determine the magnitude and direction of the force exerted by the silver car in order to80 kgprevent the black car from movingF; = 415 [KN]Mokg0 = 34.09180 kN5. Two blocks A and B of masses 60 kg and 100 kg, respectively, are positioned on a plane,which is inclined at 30 to the horizontal, as shown in the figure. Block A is preventedfrom moving by a wire attached to a wall. A force P, parallel to the inclined plane, is250 KNapplied to Block B. The coefficient of static friction between the contacting surfaces are asshown in the figure.200 KNAssuming that motion is impending,P = 121 Na) Draw the free body diagrams of Blocks A and B.T = 498 N2. A block weighing 120 kg is subjected to two forces as shown. Determine the unknownb) Determine the value of P at impending motion.force P necessary to cause an impending motion of the block to the left.c) Determine the tension T in the wire at impending motion.130 NP = 488 NH = 0.4120 kgH = 03H =033023. A block of mass M is placed on a 30 inclined plane as shown. It is subjected to a force of100 N parallel to the plane. Determine the value of M, in kg, such that the 100 N force isable to cause the block to have an impending motion up the inclined plane.100 NM = 13.7 kgEndM kg-30H = 0.28Page 1 of 2 291 words-+ 60%Type here to searchme188w^ DENG9:15 PM7/7/202023