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Hi, I am doing this problems now, and want to check the solution. Thanks, 1.

Hi, I am doing this problems now, and want to check the solution. Thanks,1. Hexavalent chromium has been identified as an inhalation carcinogen and an air toxin of concern in a number of different locales. The article "Airborned Hexavalent Chromium in Southwestern Ontario" (J. of Air and Waste Mgmnt. Assoc., 1997: 905-910) gave the accompanying data on both indoor and outdoor concentration (nanograms/m^3) for a sample of houses selected from a certain region.House--------------------------------------------------9---------------------------------------------------Indoor .07 .08 .09 .12 .12 .12 .13 .14 .15Outdoor .29 .68 .47 .54 .97 .35 .49 .84 .86---------------------------------------------------House-------------------------------------------------------------------------------------------------.18 .18 .18 .18 .19 Outdoor .28 .32 .32 1.55 .66 .29 .21 1.02-----------------------------------------------House-----------------------------------------------------------------------------------------------.28 Outdoor 1.59 .90 .52 .12 .54 .88 .49 1.24------------------------------------------------House-----------------------------------------------------------------------------------------------.39 .40 .45 .54 .62 Outdoor .48 .27 .37 1.26 .70 .76 .99 .36------------------------------------------------a. Calculate a confidence interval for the population mean difference between indoor and outdoor concentrations using a confidence level of 95%, and interpret the resulting interval.b. If a 34th house were to be randomly selected from the population, between what values would you predict the difference in concentrations to lie?c. Construct the 95% confidence intervals for the indoor and for the outdoor true concentration. Do these CIs overlap, and what does that imply about the hypothesis test in part(a)? Write a paragraph justifying your answer. Problem 2Back to the ladybugs -- recall that aphid infestation of fruit trees is usually controlled either via pesticides or via ladybug innundation. In a particular area, 2 different (and well isolated) groves, with 15 fruit trees each, are selected for an experiment. The trees in both groves are of the same age, roughly the same size, and can be assumed to be independent. One grove is sprayed with pesticides, and one is flooded with ladybugs. The fruit yield (in pounds) for each tree is given below:Pesticide trees:55.57109 36.50319 47.80090 33.34822 36.1625135.28337 41.50154 44.18931 40.81439 33.8864844.90427 49.97089 22.85414 27.84301 38.49843Ladybug trees:45.44505 35.52320 46.97865 45.76921 41.6621654.69599 58.77678 49.08538 48.53812 70.1713751.86253 39.59365 42.10194 47.39945 39.04648a) Assume that these two samples come from a normal distribution. Find the sample means of yields for the two groves, and provide the two 95% confidence intervals for the true mean yields for trees under the two treatments.b) What are the sample variances for the yields in the two groves? Test the equality of these two variances using significance level of 5%. (Write out the hypotheses, compute the test statistic, p-value, and write out the conclusion)c) Depending on your answer in (b), test the equality of the two mean yields. (Write out the hypotheses, compute the test statistic, p-value, and write out the conclusion)

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