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Hi, I need help with essay on Soil Mechanics Exercises. Paper must be at least 2500 words. Please, no plagiarized work!Download file to see previous pages... From the chart we have D10 = 0.2D30 = 0.45

Hi, I need help with essay on Soil Mechanics Exercises. Paper must be at least 2500 words. Please, no plagiarized work!

Download file to see previous pages...

From the chart we have

D10 = 0.2

D30 = 0.45

D60 = 1.20

So

Coefficient of uniformity is = D60/D30

Cu = 1.20/0.2 = 6.0

And

Coefficient of curvature of the soil is = D302/(D10 x D60)

Cc = 0.452/(0.2 x 1.2)

= 0.84375

(iv)

From the particle size distribution chart we can see that the particles are distributed over a wide range. So, this is a well graded soil.

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3 (a) At 0 m Total stress= ?= ?d hw +q = 16 (0) + 10 =10 Kpa Pore pressure = u = ?w x (h – hw) = 9.81 (0)=0 Effective stress = ?’= ? – u = 10 – 0 =10 Kpa At 1 m Total stress= ?= ?d hw +q = 16 (1) + 10 = 26 Kpa Pore pressure = u = ?w x (h – hw) = 9.81 (0) = 0 Effective stress = ?’= ? – u = 26 – 0 = 26 Kpa At 3 m Total stress= ?= ?d hw +q + ?sat (h – hw) = 16 + 10 + 20 (2) = 66 KPa Pore pressure = u = ?w x (h – hw) = 9.81 x (2) = 19.62 Kpa Effective stress = ?’= ? – u = 66 – 19.62 = 46.38 Kpa At 7 m Total stress= ?= ?d hw +q + ?sat (h – hw) = 16 + 10 + 20 (6) = 146 KPa Pore pressure = u = ?w x (h – hw) = 9.81 x (6) = 58.86 Kpa Effective stress = ?’= ? – u = 146 – 58.86 = 87.14 Kpa (b) Unit weight of silty sand = ?s= porosity * specific gravity * 9.81 = 0.54 x 2.61 x 9.81 = 14 kN/m3 Saturated weight of clay =?c= = = 17.82 kN/m3 At 0 m Total stress= ?= ?s h = 14 (0) = 0 Pore pressure = u = ?w x (h – hw) = 9.81 (0) =0 Effective stress = ?’= ? – u = 0 At 2.5 m Total stress= ?= ?s h = 14 (2.5) = 35 KPa Pore pressure = u = ?w x (h – hw) = 9.81 x (0) = 0 Effective stress = ?’= ? – u = 35 - 0 = 35 Kpa At 5 m Total stress= ?= ?s h = 14 x 5 = 70 Kpa Pore pressure = u = ?w x (h – hw) = 9.81 x (2.5) = 24.5 kPa Effective stress = ?’= ? – u = 70 – 24.5 = 45.5 Kpa At 9 m Total stress= ?= ?s h +?c (h – 5) = 14 x 9 + 17.82 (4) = 197.3 KPa Pore pressure = u = ?w x (h – hw) = 9.81 x (6.5) = 63.76 Kpa Effective stress = ?’= ? – u = 197.3 – 63.76 = 133.54 Kpa Question No. 4 (a) Shear box apparatus The soil is contained in a box which has a separate top half and bottom half.

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