Answered You can hire a professional tutor to get the answer.
Hi, need to submit a 500 words paper on the topic Simple leaner regression. Question In the CAPM model, B0 is the risk free rate of return and its value is expected to be positive (usually the Treasur
Hi, need to submit a 500 words paper on the topic Simple leaner regression. Question In the CAPM model, B0 is the risk free rate of return and its value is expected to be positive (usually the Treasury bill). The slope, B1,is the beta coefficient in CAPM model and measures the volatility of an asset’s return compared to that of the overall market. The benchmark value is 1.0 (perfect slope). The value can be more than 1.0 to show that a stock is more responsive to market changes or simply riskier than the market. The value can be less than 1.0 which indicates that the stock is less responsive to market changes (or is less risky).
Question 2
The plotted trajectories of x and y are shown in the chart below. As shown, a positive linear relationship between the two variables is expected.
Question 3
Obs
y
x
y2
χ2
yχ
=0+1χ
ɛ = y -
1
3.32
0.72
11.02
0.52
2.39
1.34
1.98
2
1.40
1.68
1.96
2.82
2.35
2.12
- 0.72
3
0.65
- 0.72
0.42
0.52
- 0.47
0.19
0.46
4
0.93
0.81
0.86
0.66
0.75
1.42
- 0.49
5
- 1.21
- 0.35
1.46
0.12
0.42
0.49
- 1.70
6
- 1.62
- 2.30
2.62
5.29
3.73
- 1.08
- 0.54
7
1.41
0.80
1.99
0.64
1.13
1.41
0.00
8
0.18
0.40
0.03
0.16
0.07
1.09
- 0.91
9
1.88
- 0.65
3.53
0.42
- 1.22
0.24
1.64
10
1.35
0.39
1.82
0.15
0.53
1.08
0.27
Total
8.29
0.78
25.74
11.30
9.68
8.29
-
Completed table
obs
Y
X
SQY
SQX
YX
Y_HAT
E
1
3.32
0.72
11.02240
0.518400
2.390400
1.355465
1.964535
2
1.40
1.68
1.960000
2.822400
2.352000
2.091122
-0.691122
3
0.65
-0.72
0.422500
0.518400
-0.468000
0.251979
0.398021
4
0.93
0.81
0.864900
0.656100
0.753300
1.424433
-0.494433
5
-1.21
-0.35
1.464100
0.122500
0.423500
0.535513
-1.745513
6
-1.62
-2.30
2.624400
5.290000
3.726000
-0.958791
-0.661209
7
1.41
0.80
1.988100
0.640000
1.128000
1.416770
-0.006770
8
0.18
0.40
0.032400
0.160000
0.072000
1.110246
-0.930246
9
1.88
-0.65
3.534400
0.422500
-1.222000
0.305620
1.574380
10
1.35
0.39
1.822500
0.152100
0.526500
1.102583
0.247417
Eviews Summary Descriptive Results
Y
X
SQX
SQY
YX
Y_HAT
E
 .Mean
 .0.829000
 .0.078000
 .1.130240
 .2.573570
 .0.968170
 .0.863494
-0.034494
 .Std. Dev.
 .1.447730
 .1.117615
 .1.659833
 .3.141602
 .1.482091
 .0.856439
 .1.136141
 .Sum
 .8.290000
 .0.780000
 .11.30240
 .25.73570
 .9.681700
 .8.634939
-0.344939
 .Sum Sq. Dev.
 .18.86329
 .11.24156
 .24.79541
 .88.82698
 .19.76935
 .6.601388
 .11.61734
 .Observations
 .10
 .10
 .10
 .10
 .10
 .10
 .10
Question 4
The slope (β0) = (0.620455)(1.45)/(1.12) = 0.804
The intercept (β1) = 0.83 – (1.01)(0.08) = 0.766.
Question 5
SSR = Sum of (Predicted y – population mean of y)^2 = 6.6132
SSR
 .Mean
 .0.661329
 .Median
 .0.305059
 .Maximum
 .3.196195
 .Minimum
 .0.074847
 .Std. Dev.
 .0.994800
 .Skewness
 .1.938750
 .Kurtosis
 .5.352234
 .Jarque-Bera
 .8.570002
 .Probability
 .0.013774
 .Sum
 .6.613286
 .Sum Sq. Dev.
 .8.906647
 .Observations
 .10
Question 6
Variance of returns, σ2 = 2.10
Standard deviation of returns, y, σ = 1.45
Standard deviation, x = 1.12
Question 7
The slope is 0.804 and the p-value is 0.056. At 5% level of significance, the slope is not significantly different from zero. The intercept is 0.766 and the p-value is 0.079. At 5% level, the intercept is not significantly different from zero.
Variable
Coefficient
Std. Error
t-Statistic
Prob. . .
C
0.766310
0.381844
2.006865
0.0797
X
0.803721
0.359171
2.237714
0.0556
R-squared
0.384964
 . . . .Mean dependent var
0.829000
Adjusted R-squared
0.308084
 . . . .S.D. dependent var
1.447730
S.E. of regression
1.204243
 . . . .Akaike info criterion
3.386435
Sum squared resid
11.60160
 . . . .Schwarz criterion
3.446952
Log likelihood
-14.93218
 . . . .Hannan-Quinn criter.
3.320048
F-statistic
5.007366
 . . . .Durbin-Watson stat
1.877887
Prob(F-statistic)
0.055623
Question 8
Testing whether the slope, 0.804, is bigger or lower than 1 is a one-tailed t-test. Since the calculated t-statistic is below the rejection level, we cannot reject the null hypothesis that the slope is significantly lower than 1. The stock is not more volatile than the market.
Wald Test:
Equation: EQ_CAPM_REG
Test Statistic
Value
df
Probability
t-statistic
-0.612004
 .8
 .0.5575
F-statistic
 .0.374549
(1, 8)
 .0.5575
Chi-square
 .0.374549
 .1
 .0.5405
Null Hypothesis: C(1) = 1
Null Hypothesis Summary:
Normalized Restriction (= 0)
Value
Std. Err.
-1 + C(1)
-0.233690
 .0.381844
Restrictions are linear in coefficients.
Question 9
SSE = 11.60
SST = SSE + SSR = 11.60 + 7.26 = 18.86
Question 10
Correlation coefficient = 0.62 (Excel I21)
Coefficient of determination, r2 = 0.622 = 0.38
Question 11
Done and tables pasted in the questions above.